Formula for lengths of a rectangle - why does it give both lengths?

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Why does the formula [P±√(P^2-16A)]/4 give the values of either of two different lengths of a rectangle? (P is perimeter and A is area)

I derived it by solving two simultaneous equations, A = xy and P=x+y and then applying the quadratic formula to the resulting second-order equation 2y^2 + Py+2A thus getting y=[P±√(P^2-16A)]/4

I tried out some numbers just to test it out and was surprised that both solutions were lengths of the rectangle, so it gave y but also x…I fail to see how this so, shouldn't it only give the length y (or x, if I'd eliminated y instead when I solved the simultaneous equations)?

Thanks
 
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The equations cannot 'know' which is x and which is y. If x = A, y = B is a solution then so is x = B, y = A.
Btw, the perimeter would be 2x+2y.
 
haruspex said:
The equations cannot 'know' which is x and which is y. If x = A, y = B is a solution then so is x = B, y = A.
Btw, the perimeter would be 2x+2y.

I believe its a typo, his derivation is correct in the quadratic formula, the quadratic had a sign error also
 
Hmmm...I guess that makes sense...I'll think about it, thanks.
 
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