This does look like coursework, so I'll move the thread to the Homework Help forums.
And as Redbelly says, a.a, are you familiar with the standard formula for the energy of a photon in terms of its wavelength (or frequency)? It should be in your textbook, or you could find it by searching on "photon" at wikipedia.org.
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when i searched on wikki i only found E= hc all ever lambda
but all these are given, we have the energy, the wave length and both constants
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nevermind.. just realized i was being stupid, so if wavelength is 656nm abd we need 10 J then this would be what we need to do, can someone please check this? thx.
E = hc/lanbda = ...= 3.0299 * 10^-19 J
then that means one photon gives 3.0299 * 10^-19 J
so to get 10 J: 10 J --> 10/3.0299 * 10^-19 = 3.3 * 10^19 photons
ANS: 3.3*10^19 photons needed to produce 10 J
sorry I am not familiar with how you post eqn the proper way
If you don't need the full features of Latex, you can also copy-and-paste a lot of math symbols from here:
https://www.physicsforums.com/blog.php?u=122961
For example:
E = hc/λ
Hi,
I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem.
Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$
Where ##b=1## with an orbit only in the equatorial plane.
We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$
Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units,
According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##,
## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units.
So is this conversion correct?
Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?