Foucault pendulum and a round globe

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xaratustra
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Imagine we are all cavemen without satellite technology and just discovered the Foucault pendulum! As we know the angle of presession depends on the latitude. This can be used to prove that the Earth is rotating, right? Now by putting several Foucault pendula around the Earth, at equidistant longitude and latitude, can we prove that the Earth is a sphere as well?
 
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xaratustra said:
Now by putting several Foucault pendula around the Earth, at equidistant longitude and latitude, can we prove that the Earth is a sphere as well?
You could exclude a lot of potential shapes, and by assuming certain smoothness between your sample positions narrow it down to a sphere.
 
cool. then all pendula must be installed at the same altitude to guarantee smoothness. :smile:
 
xaratustra said:
cool. then all pendula must be installed at the same altitude to guarantee smoothness. :smile:
It's not about the altitude, but how densely they are spaced.

Also, since pendulums are based on gravity, you have to assume some model of gravity, which by itself might already imply an equipotential surface, without even the need for swinging pendulums.
 
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xaratustra said:
Imagine we are all cavemen without satellite technology and just discovered the Foucault pendulum! As we know the angle of presession depends on the latitude. This can be used to prove that the Earth is rotating, right? Now by putting several Foucault pendula around the Earth, at equidistant longitude and latitude, can we prove that the Earth is a sphere as well?

Wouldn't it be much easier for them to just glance at the sky and notice how the position of the North Star varies with latitude?
(Flaw: The North Star moves, it was not north in all periods of history.)
 
If it was (very) cloudy all over the Earth, it would be harder to arrive at an initial Geocentric model Universe but the Fuocault pendulums would definitely indicate rotation. No one would every have moved to a Heliocentric model, I reckon ('till Radio came along).