Fourier Series- half range sine series

Click For Summary
SUMMARY

The discussion focuses on computing the half-range sine series for the function f(x) = x over the interval [0, p]. The formula for the coefficients is established as bn = (2/p) * ∫(from 0 to p) x * sin(nπx/p) dx. Integration by parts is utilized to derive the coefficients, resulting in bn = 2[(-p * cos(nπ)/nπ) + (p * sin(nπ)/n²π²)]. The series is then applied to demonstrate the convergence of the series 1 - (1/3) + (1/5) + ... = π/4.

PREREQUISITES
  • Understanding of Fourier series, specifically half-range sine series.
  • Proficiency in integration techniques, particularly integration by parts.
  • Familiarity with trigonometric identities involving sine and cosine.
  • Knowledge of convergence of infinite series.
NEXT STEPS
  • Study the derivation of Fourier series coefficients in detail.
  • Learn about the convergence properties of Fourier series.
  • Explore applications of half-range sine series in solving boundary value problems.
  • Investigate the relationship between Fourier series and other series expansions, such as Taylor series.
USEFUL FOR

Students and educators in mathematics, particularly those studying Fourier analysis, as well as anyone interested in applying Fourier series to solve practical problems in physics and engineering.

Kamekui
Messages
12
Reaction score
0

Homework Statement


Let f(x)=x, 0≤x≤p

(a.) Compute the half-range sine series
(b.) Use the series to show that 1-(1/3)+(1/5)+...=π/4


Homework Equations



bn=(2/L)*int(from 0 to L) f(x)*sin(nπx/L) dx

The Attempt at a Solution



bn=(2/p)*int(from 0 to p) x*sin(nπx/p) dx

Using integration by parts I get:

bn= 2[(-p*cos(nπ)/nπ) + (p*sin(nπ)/n2π2)]

I'm not really sure where to go from here, any help is appreciated.
 
Physics news on Phys.org
Since n is an integer, you can simplify ##\cos n\pi## and ##\sin n\pi##.
 

Similar threads

  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 104 ·
4
Replies
104
Views
8K
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K