Fourier Series: Rewriting with k_n and θ

twotaileddemon
Messages
258
Reaction score
0

Homework Statement



Show that the Fourier series f(x) = \sumansin(nx) + bncos(nx) can be written as \sumkn(cos(nx+\vartheta)) and define kn and \vartheta

where the summation is from 0 to \infty

Homework Equations


sin \vartheta = cos (90 - \vartheta) ??

The Attempt at a Solution


Well what I originally did was replace the sin term by cos (90 - nx), put cosine in terms of complex exponentials, and then try to solve the equation, but I only got what I was given in the first place and not the solution (i.e. I went in a circle).

Is there some kind of property of sin or cos I could use?
 
Physics news on Phys.org
Think about something like this:

a \cos x + b \sin x = \sqrt{a^2+b^2}\ \left(\frac a {\sqrt{a^2+b^2}}\cos x +\frac b {\sqrt{a^2+b^2}}\sin x\right )

and then think about what the expansion of

\cos{(x -\phi)}

looks like.
 
Try expanding k_n\cos(nx+\theta_n) using the angle addition trig identity.
 
Thank you for the responses - I was able to derive the proof exactly.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top