Fourier Series - Summation to Integral

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Homework Help Overview

The discussion revolves around deriving equations related to Laplace's equation in rectangular coordinates, specifically focusing on the transition from summation to integral forms in the context of Fourier series. The original poster expresses confusion regarding the derivation of coefficients in the Fourier series representation of a function.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the summation and integral forms of Fourier series coefficients. The original poster questions how to derive the coefficients and expresses uncertainty about the process. Others suggest methods for finding coefficients through integration, referencing previous experiences with similar problems.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the integration process for finding coefficients, but there is no explicit consensus on the original poster's confusion about the transition from summation to integral.

Contextual Notes

The original poster mentions a lack of specific problem details and boundary values, indicating that further information could be provided if necessary. This may affect the clarity of the discussion.

erok81
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Homework Statement



My question involves the mid-point in deriving some of the equations to solve Laplace's equation in rectangular coordinates. The question may no make sense as it isn't problem specific. I can provide boundary values if necessary - just let me know.

Homework Equations



I've included a photo of how the example problem is broken up. For my question we'll choose subproblem #1.

[tex]u(x,y)=\sum^{\infty}_{n=1} A_{n} sin \frac{n \pi x}{a}sinh\frac{n\pi(b-y)}{a}[/tex]

[tex]A_{n}= \frac{2}{a sinh \frac{n \pi b}{a}} \int^{a}_{0} f(x) sin \frac{n \pi x}{a} dx[/tex]

The Attempt at a Solution



I don't understand how I get from the summation to the integral so I can solve for An. I see the pattern and transform the four summations in the example, but I'd really like to know the how/why it's done.

Let me know if I need to include anymore information as I don't have much regarding the actual problem. :smile:
 

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The non-zero boundary condition is

[tex]f(x) = u(x,0) = \sum^{\infty}_{m=1} \left(A_m\sinh\frac{m\pi b}{a}\right) \sin \frac{m \pi x}{a}[/tex]

which is a Fourier series where the quantity in the parentheses is the m-th coefficient. Do you know how solve for the coefficients of a Fourier series?
 
I thought I knew how to find them.

When we were doing one dimensional waves I could find them no problem.

Where I'd have something like this.

[tex] \sum^{\infty}_{n=1} \left(B_{n} cos\lambda_{n}t+B^{*}_{n}sin\lambda_{n}t)sin(n \pi x)[/tex]

To solve for Bn I'd take u(x,0)=f(x) and integrate.

[tex]\int^L_{-L} f(x) sin \frac{n \pi x}{L} dx[/tex]

And then for the B*n I'd take ut(x,0) = g(x) and do the same thing.

[tex]\int^L_{-L} g(x) sin \frac{n \pi x}{L} dx[/tex]

Then the next chapter came up using 1D heat equation and the f(x) was given (and was no longer u(x,0) like the above example. Since it was always given I just threw it into it's appropriate location and solved away. Now, because I never knew why the f(x) became what it is, I am even more confused on how to find them.

So to answer you question, I guess I don't know how to find them. :redface:
 
Suppose you have

[tex]f(x) = \sum_{m=1}^\infty b_m \sin \frac{m\pi x}{L}[/tex]

Multiply both sides by sin (nπx/L) and integrate from 0 to L. Use the fact that

[tex]\int_0^L \sin \frac{m\pi x}{L}\sin \frac{n\pi x}{L}\,dx = \frac{L}{2}\delta_{mn}[/tex]

where δmn is the Kronecker delta.
 

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