Question: Is the Fourier Transform of a Hermitian operator also Hermitian?(adsbygoogle = window.adsbygoogle || []).push({});

In the case of the density operator it would seem that it is not the case:

[tex]\rho(\mathbf{r}) = \sum_{i=1}^N \delta(\mathbf{r}-\mathbf{r}_i)[/tex]

[tex]\rho_k = \sum_{i=1}^N e^{-i\mathbf{k} \cdot \mathbf{r}}[/tex]

I have a hard time believing that the FT wouldn't be Hermitian though since an obverservable in one space should be an observable in another space.

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# Fourier Transform of Hermitian Operators

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