Frames of Reference on Top of a Moving Train

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When an object is thrown from a moving train, the frames of reference involved can be classified as inertial if the train's velocity is constant. The principle of relativity indicates that the object will travel the same relative distance as if thrown from a stationary position, assuming air resistance is negligible. However, some argue that the train's curvature path implies a form of acceleration, complicating the inertial frame classification. A key point of contention arises when comparing distances traveled by the object relative to observers on the train versus the ground. Ultimately, the discussion highlights the complexities of motion and reference frames in physics.
ZachBirnski
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When an object is thrown by someone standing on top of a moving train, which variations of "frames of reference" would apply? (i.e. inertial, non-inertial, etc.) How would this principle work? (The object would go the same relative distance as it would if thrown from a person standing on motionless ground, disregarding air resistance of course)
 
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You'll have to clarify the question. If the train is accelerating relative to the Earth, it is a non-inertial frame.
 
Brian_C said:
You'll have to clarify the question. If the train is accelerating relative to the Earth, it is a non-inertial frame.

The train isn't accelerating; its velocity is constant. More focus is placed on the action of the object being thrown forward in respects to the moving train than the motion of the train.
 
It is inertial motion and the principle of relativity applies: you can play "catch" in the cabin of a moving train exactly the same if it is moving or not.
 
russ_watters said:
in the cabin of a moving train

Or on top of the train, provided of course that you're not going fast enough to make the wind a factor.
 
ZachBirnski said:
The train isn't accelerating; its velocity is constant.
I never thought of this before, but this particular comment snagged my attention. To some extent, the train is, in fact, accelerating. It is following the curvature of the Earth, which means that its path is actually circular rather than linear. I might be misunderstanding some official terminology, but that constant 'downward' change of vector implies to me an acceleration.
 
ZachBirnski said:
The object would go the same relative distance as it would if thrown from a person standing on motionless ground, disregarding air resistance of course

Assume a person on the platform uses energy E to throw a ball in the direction the train is heading and the ball lands on the ground 100 feet in front of him.
Suppose again that a person standing on the train throws a ball in the same direction, using the same amount of energy to do so. Relative to the person on the train, the ball falls to the ground far closer than 100 feet.
In light of this, how can the object "go the same relative distance..."?
 
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