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## Homework Statement

A square aperture with a side of length 0.5 mm is illuminated with light of wavelength 550 nm. At what distance from the aperture would the Fraunhofer diffraction pattern have a central maximum with a width also equal to 0.5 mm? What can you say about the Fraunhofer condition under these circumstances?

## Homework Equations

W

^{2}/ Lλ << 1

where

W : aperture or slit size

L : distance from aperture

λ : wavelength

3. The Attempt at a Solution

3. The Attempt at a Solution

0.5mm = 0.0005m

550 nm = 5.5*10

^{-7}m

L = W

^{2}/ λ

= (0.0005m)

^{2}/ 5.5*10

^{-7}m

= 45 cm - distance at which Fraunhofer diffraction pattern is observed

I'm a bit lost with this question / Fraunhofer diffraction. I think I may have used the wrong equation maybe. Any help would be much appreciated.