Free and bound charge at dielectric-conductor interface

AI Thread Summary
In a capacitor with a linear dielectric in an electrostatic setup, a uniform electric field exists inside the capacitor, while the field within the electrodes remains zero. The dielectric material polarizes, resulting in bound charge at the dielectric-conductor interface. However, the conductor's surface charge creates the electric field, and the dielectric itself is effectively uncharged despite its polarization. Induced free charge from the conductor does not contribute to the net charge at the interface. Understanding the distinction between polarization and charge is crucial in analyzing the behavior at the conductor-dielectric interface.
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Say I have a capacitor filled with a linear dielectric in a purely electrostatic setup. Then there will exist a uniform electric field inside the capacitor, and the field inside the electrodes is of course zero. The dielectric will polarize, and I should get bound charge at the dielectric-conductor interface. It seems to me that you would also get some induced free charge from the conductor as well at this interface.

What kind of coulomb forces would I get in this situation, if what I described is in fact correct?

To generalize my question, what in general happens at a conductor-dielectric interface? How does the induce charge behave? Is there only surface polarization charge from the dielectric, or does induced free charge come into play from the conductor?

Thanks!
 
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Actually, you have it exactly backwards. There is an applied charge on the surface of the conductor that causes the E-field between the plates. The dielectric material polarizes in response to this externally applied E-field. For all practical purposes the dielectric is uncharged, including on its surface. Being polarized is not the same as being charged.
 
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