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What is the motion (acceleration:linear as well as rotational) of the cylinder?

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- Thread starter ash1262
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- #1

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What is the motion (acceleration:linear as well as rotational) of the cylinder?

- #2

tiny-tim

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hi ash1262!

tell us what*you* think, and why, and then we'll comment!

tell us what

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tiny-tim

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what is the equation showing the effect of F on the linear motion?

what is the equation showing the effect of F on the rotational motion?

- #5

BruceW

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That is good, you are thinking along the right lines. The 'no-slip' condition is the starting place for this problem. And as you suggest, this means the total acceleration of the bit of the cylinder next to the surface must be equal to the acceleration of the surface. But, the total acceleration of the bit of the cylinder near the surface is not equal to the linear acceleration of the cylinder. What other kind of acceleration contributes?ash1262 said:The solution says that the linear acceleration of the cylinder is 3/2 times acceleration of the platform, which I can't visualize. I feel it should be same as that of the platform as there is no slipping

- #6

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There is no slipping but there is rolling

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- #8

BruceW

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##\vec{v}= \dot{r} \hat{r} + r \dot{\theta} \hat{\theta} = \dot{x} \hat{x} + \dot{y} \hat{y}##

So I'm thinking "don't worry, underneath it all is a nice inertial reference system, with Cartesian coordinates". haha. p.s. the 'hooray' is not meant to be sarcastic. Often people think I'm being sarcastic when I'm not.

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Thanks for the encouragement.

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