Free Fall Acceleration fractures Problem

AI Thread Summary
Falls leading to hip fractures are a significant risk for the elderly, with impact speeds typically around 2.0 m/s. Reducing this speed to 1.3 m/s or less can prevent fractures, and elastic hip pads can help achieve this. A calculation was performed to determine the necessary acceleration when a hip pad compresses by 2.0 cm, yielding an acceleration of 57.75 m/s². The user expressed concern about the accuracy of their solution, and a response suggested trying a different compression value of 3.0 cm to see if that resolves the issue. The discussion highlights the importance of accurate calculations in preventing serious injuries from falls.
tater08
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Homework Statement


Falls resulting in hip fractures are a major cause of injury and even death to the elderly. Typically, the hip’s speed at impact is about 2.0 m/s. If this can be reduced to 1.3 m/s or less, the hip will usually not fracture. One way to do this is by wearing elastic hip pads.

If a typical pad is 5.0 cm thick and compresses by 2.0 cm during the impact of a fall, what acceleration (in m/s^2) does the hip undergo to reduce its speed to 1.3 m/s?

Homework Equations


(y1-y0)=(Vf^2-V0^2)/2a


The Attempt at a Solution


y1-yO=-2 cm = 0.02M Vf= 1.3 V0=2.0 a=?
1.3^2-2.0^2 =-2.31

(-2.31m^2/s^2)/ 2*-0.02m =a a= 57.75m/s^2

question is...did i do this problem right because this is an online homework problem and i keep getting it wrong so I'm wondering if it is the program or if it just me.

thanks
 
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tater08 said:
Typically, the hip’s speed at impact is about 2.0 m/s. If this can be reduced to 1.3 m/s or less, the hip will usually not fracture. One way to do this is by wearing elastic hip pads.

If a typical pad is 5.0 cm thick and compresses by 2.0 cm during the impact of a fall, what acceleration (in m/s^2) does the hip undergo to reduce its speed to 1.3 m/s?

Hi tater08! :smile:

Your answer looks fine to me! :smile:

I think it must be a misprint …

hmm :rolleyes: … try using 3.0 cm instead of 2.0 cm, and see if the computer accepts that! :smile:
 
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