Free Fall and the Accelaration of Gravity

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To find the total maximum height and total travel time of an object thrown into the air, one can use kinematic equations. Given that the object reaches 50% of its maximum height in 2 seconds, it can be inferred that the time to reach maximum height is 4 seconds. Using the formula for displacement, the maximum height can be calculated as 50% of the total height at this time. The total travel time is twice the time taken to reach maximum height, resulting in an overall travel time of 8 seconds. This problem can be resolved with the provided data and appropriate kinematic equations.
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If I were to throw an object in the air from the ground and it would reach 50% of its maximum height in 2 seconds, how does one find the object's total maximum height and total travel time?

This is the last question in my 1D kinematics chapter. I've been successful in resolving my other assigned questions but I can not wrap my mind around this one. In comparaison to the others, the question seems to be lacking sufficient data for me to able to resolve it. Any guidance would be appreciated. Thanks!
 
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There is sufficient data to solve the question.

The template you deleted is there for a reason - So we can provide better help, rather than teasing info piecewise out of you. Fill it out and we'll go from there:

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