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## Homework Statement

a ball is thrown straight down from the top of a 220 feet building with an initital velocity of -22ft/s. What is the velocity of the ball after 3 seconds? What is the velocity of the ball after falling 108 feet?

## Homework Equations

s(t) = -16t^2 + Vi(t) + si vi = initial velocity, si = initial position

## The Attempt at a Solution

s(t) = -16t^2 +Vi(t) +si

= -16t^2 - 22ft/s + 200ft

V(t) = -32(t) - 22ft/s

V(3) = -96 ft/s - 22ft/s = -118 ft/s

I can seem to figure out how to determine the velocity of the ball after it has dropped 108ft.

I should be able to do this, but i'm missing something, somewhere on what should be pretty basic.

Thanks for any guidance!