Free fall ball velocity question

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SUMMARY

The discussion centers on calculating the velocity of a ball thrown straight down from a 220-foot building with an initial velocity of -22 ft/s. After 3 seconds, the ball's velocity is determined to be -118 ft/s using the equation V(t) = -32t - 22 ft/s. To find the velocity after the ball has fallen 108 feet, two methods are suggested: using the equation V_f^2 = V_i^2 - 2gΔy or calculating the time to drop 108 feet with y = V_i t - 1/2 g t^2 and then applying V_f = V_i - gt.

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Homework Statement


a ball is thrown straight down from the top of a 220 feet building with an initital velocity of -22ft/s. What is the velocity of the ball after 3 seconds? What is the velocity of the ball after falling 108 feet?


Homework Equations


s(t) = -16t^2 + Vi(t) + si vi = initial velocity, si = initial position


The Attempt at a Solution


s(t) = -16t^2 +Vi(t) +si
= -16t^2 - 22ft/s + 200ft

V(t) = -32(t) - 22ft/s
V(3) = -96 ft/s - 22ft/s = -118 ft/s

I can seem to figure out how to determine the velocity of the ball after it has dropped 108ft.

I should be able to do this, but I'm missing something, somewhere on what should be pretty basic.

Thanks for any guidance!
 
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msc8127 said:

Homework Statement


a ball is thrown straight down from the top of a 220 feet building with an initital velocity of -22ft/s. What is the velocity of the ball after 3 seconds? What is the velocity of the ball after falling 108 feet?


Homework Equations


s(t) = -16t^2 + Vi(t) + si vi = initial velocity, si = initial position


The Attempt at a Solution


s(t) = -16t^2 +Vi(t) +si
= -16t^2 - 22ft/s + 200ft

V(t) = -32(t) - 22ft/s
V(3) = -96 ft/s - 22ft/s = -118 ft/s

I can seem to figure out how to determine the velocity of the ball after it has dropped 108ft.

I should be able to do this, but I'm missing something, somewhere on what should be pretty basic.

Thanks for any guidance!

There are two ways to do it.

The quickest way is to use [tex]V_f^2 = V_i^2 - 2 g \Delta y[/tex].

The other ways is to use the equation [tex]y= V_i t -1/2 g t^2[/tex] to first find the time to drop 108 feet and then to plug this into [tex]V_f = V_i - g t[/tex]
 
Thanks for the reply. I have a solution that makes sense now. :)

I appreciate your help!
 

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