a ball is thrown straight down from the top of a 220 feet building with an initital velocity of -22ft/s. What is the velocity of the ball after 3 seconds? What is the velocity of the ball after falling 108 feet?
s(t) = -16t^2 + Vi(t) + si vi = initial velocity, si = initial position
The Attempt at a Solution
s(t) = -16t^2 +Vi(t) +si
= -16t^2 - 22ft/s + 200ft
V(t) = -32(t) - 22ft/s
V(3) = -96 ft/s - 22ft/s = -118 ft/s
I can seem to figure out how to determine the velocity of the ball after it has dropped 108ft.
I should be able to do this, but i'm missing something, somewhere on what should be pretty basic.
Thanks for any guidance!