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Free fall

  1. Oct 11, 2009 #1
    1. The problem statement, all variables and given/known data

    A flowerpot falls past two meter tall window in ¼ of a second. From what height did the flowerpot fall?

    2. Relevant equations

    To calculate the velocity of the pot while this is passing the window: v = d/t
    To calculate the height: v^2= v0^2 = 2gh → h= (v^2 - v0^2) / 2g

    3. The attempt at a solution

    v = d/t = 2m / (1/4s) = 8 m/s

    Since the initial velocity is 0, do we plug the 8m/s in place of the v squared, so the equation would be h= (8 m/s)^2 - 0 / 2 * 9.8 m/s^2 and the final answer should be 3.27m, right?!?!
     
  2. jcsd
  3. Oct 11, 2009 #2

    rl.bhat

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    Homework Helper

    While crossing the window, the flower pot is not moving with constant velocity. So your calculation of velocity is wrong.
    Initial velocity of the flower pot vo = 0.
    If the top edge of the window is at a height h, then
    h = 1/2*g*t^2.
    The bottom of the window is at a height h' =...?
    Now h' = 1/2*g*(...)^2 ?
     
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