1. The problem statement, all variables and given/known data A flowerpot falls past two meter tall window in ¼ of a second. From what height did the flowerpot fall? 2. Relevant equations To calculate the velocity of the pot while this is passing the window: v = d/t To calculate the height: v^2= v0^2 = 2gh → h= (v^2 - v0^2) / 2g 3. The attempt at a solution v = d/t = 2m / (1/4s) = 8 m/s Since the initial velocity is 0, do we plug the 8m/s in place of the v squared, so the equation would be h= (8 m/s)^2 - 0 / 2 * 9.8 m/s^2 and the final answer should be 3.27m, right?!?!