Frequency of Siren Perceived at 50m After Fire Engine Passes

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SUMMARY

The discussion focuses on calculating the perceived frequency of a siren from a fire engine traveling at 80 km/h, using the Doppler effect. The speed of sound in air is given as 343 m/s, and the siren emits a frequency of 440 Hz. For the scenario where the observer is 50m behind the fire engine, the correct application of the generalized Doppler equation results in a perceived frequency of 440 Hz multiplied by the factor derived from the equation f' = [V/(V+Vs)]f, where Vs is the speed of the source. The analysis confirms that the observer is stationary, simplifying the calculations.

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Homework Statement


Assume that the speed of sound in the air is V=343m/s. Use the generalized form of the Doppler equation to solve the following problem.
You are standing 100m away from a long straight road while a fire engine passes by along the road. The fire engine is equipped with a siren which emits a steady frequency of 440Hz. If the fire engine is traveling at 80km/h along the road, what frequency do you preceive for the siren
(a) 100m (measured along the road) before the fire engine passes
(b) 50m (measured along the road) after the fire engine passes


Homework Equations



generalized form of the doppler equation: f ' = [(V + Vocos(θo))/(V-Vscos(θs))]f

The Attempt at a Solution



(b) if the source and the observer are moving away from each other, we have: θs - θo = 180 and since cos180 = -1, we get the equation f ' = [ V/(V+Vs)]f with negative values for both Vo and Vs.
 
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I think that in your question the observer is not moving .. your equation is correct f` = (v/(v+vs))f , was that your question or you have other questions?
 

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