Frictional coin sliding on turntable

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To determine the maximum rpm of a turntable without a 5.0 g coin sliding off, the centripetal force must equal the maximum static friction force. The static friction force is calculated using the formula F_friction = µs * N, where N is the normal force (mg). The maximum centripetal force is given by F_net = m(v^2/r), where v is the tangential speed. By equating the maximum static friction force to the centripetal force and solving for speed, the result can then be converted to rpm. Properly applying these equations will yield the correct maximum rpm before the coin slips.
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A 5.0 g coin is placed 22 cm from the center of a turntable. The coin has static and kinetic coefficients of friction with the turntable surface of µs = 0.80 and µk = 0.50. What is the maximum rpm that the turntable could speed up to without the coin sliding off?
m = .005 kg
r = .22 m
µs = 0.8

Equations found..
v = angular velocity * r
Force(net) = m(v)^2 / r

Inertia > µs N when coin slips (?)

I believe this gets set equal to mg (Normal Force) but I haven't been able to generate the correct answer multiplying µs as a coefficient of either side.

I'm not sure what isn't being accounted for, what do I do?
 
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You're heading in the right direction. Answer these questions:
(1) What force provides the centripetal force on the coin?
(2) What's the maximum value of that force?

Use that maximum value of force in your centripetal force equation to calculate the maximum speed. Then express that answer in rpm.

Do Not Double Post!
 
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