AJDangles
- 48
- 0
Doc Al said:Yes, the triangle you've drawn is incorrect. (But the direction of the force and tangent line are correct, which is what I was focusing on. Sorry about not pointing that out!) Since you are finding components of the weight, you must draw a new right triangle in which the weight is the hypotenuse.
Sanity check: A vector must always be bigger (or at least equal to) its components. So when drawing a right triangle to find components, the components must be the smaller sides, not the hypotenuse.
Ok. I drew my triangle with the mg. I found the components to be:
x = mgcos30
y = mgsin30
We're looking for the x component as the acceleration, so then we can go: mgcos30 = ma. Cancel out the masses, solve for acceleration.
a = gcos30
a = 8.5units/s^2
Right? (Please say yes... ha ha)