From Planck's law to derive the stefan Boltzman constant.

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SUMMARY

The discussion focuses on deriving the Stefan-Boltzmann constant from Planck's law of black body radiation. The key equation presented is $$\frac{\sigma T^4}{\pi}=\int\limits_{0}^{+\infty} L_{\lambda}(\lambda,T) \, d \lambda$$, where $$L_{\lambda}(\lambda,T)=\frac{2hc^2}{\lambda^5 (exp^{(hc)/(\lambda k_B T)}-1)}$$. The derivation involves integrating the density of radiative energy, $$\rho({\lambda})$$, as defined in the context of black body radiation. Reif's Statistical Physics book is cited as a resource for further understanding this derivation.

PREREQUISITES
  • Understanding of Planck's law for black body radiation
  • Familiarity with the Stefan-Boltzmann law
  • Knowledge of statistical mechanics concepts
  • Basic proficiency in calculus for integration
NEXT STEPS
  • Study the derivation of the Stefan-Boltzmann law from Planck's law
  • Explore Reif's Statistical Physics for detailed explanations
  • Learn about the implications of black body radiation in thermodynamics
  • Investigate applications of the Stefan-Boltzmann constant in astrophysics
USEFUL FOR

Physicists, students of thermodynamics, and researchers in statistical mechanics will benefit from this discussion, particularly those interested in the mathematical foundations of black body radiation and its applications.

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The following is the Planck's derivation for black body radiation
$${\rho}({\lambda}) d{\lambda}=E({\lambda})*f({E(\lambda}))*D({\lambda})d{\lambda}------equation 1$$
$$\int_0^\infty{\rho}({\lambda})d{\lambda}$$ is the density of radiative energy.
From
http://en.wikipedia.org/wiki/Stefan–Boltzmann_law#Derivation_from_Planck.27s_law

"... is the amount of energy per unit surface area per unit time per unit solid angle emitted at a frequency by a black body at temperature T." From Wikipedia .
How should I derive the I(v,T) from Planck's law? Please help .thanks
 
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## \frac{\sigma T^4}{\pi}=\int\limits_{0}^{+\infty} L_{\lambda}(\lambda,T) \, d \lambda ##, where ## L_{\lambda}(\lambda,T)=\frac{2hc^2}{\lambda^5 (exp^{(hc)/(\lambda k_B T)}-1)} ##.
##\\ ## ## \sigma=\frac{\pi^2 k_B^4}{60 \hbar^3 c^2} ##.
## \\ ## This last result is not straightforward, but Reif derives it in an Appendix of his Statistical Physics book.
 
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