Fulcrum, balance point and scissor lift force

AI Thread Summary
The discussion revolves around calculating counterweights and forces for a scissor lift design using "X" sections. The user seeks clarification on whether the weight of the beam itself affects the balance and how to account for it in their calculations. They also inquire about the force required to push the pivots apart and the necessary torque for a motorized lead screw system. Visual aids are suggested to better understand the arrangement and mechanics involved. Overall, the user requests simplified explanations suitable for a younger audience to grasp the concepts of balance and force.
cristofayre
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My first question, so be kind (!)

Long time since I was at school, and can only remember the basics of beams and fulcrums. In essence, that a 1kg weight 5mtrs from a fulcrum / pivot needs 5kg at 1mtr to counterbalance. But what about the beam itself? Do the two sides cancel each other out?

For example, I plan to create a "XXX" scissor / accordian arrangement. The metalwork is in ten "X" sections, each approx 1kg, and extends to 5mtrs. One kg weight on the end. The counterweight side has 1.5 "X" sections. All things equal, that gives a c/w of 3kg ... but doesn't account for the 10kg of beam metalwork. So how to calculate the counterweight required. Any ideas how to proceed?

Next (related) question. If the "X" were vertical, (they're not: At most 45 degrees) How much 'force' is needed to push the pivots in the middle of the "XX" apart. (My current thinking is a 8mm lead screw that has to rotate 40 times to cover the 300mm travel). If that's motorised, what sort of torque would that motor need? ... if it's even practical. Since the outer edges of the X are extending the next section, they must (in theory) be adding to the friction forces, (they will be bolts acting as pivots, not ball bearings)

Now whilst this question may appear that I have a smattering of knowledge on the subject, it's exactly that: basics. All the online formulaes that deal with "Newton/Meters", gravity, force, torque and all the other variables leave me out in the cold. So if poss, can you give any answer in "schoolboy" basics that someone of 12 ~ 14 could comprehend, (alas, I'm physically 4x that age range) Or simply say: You need XYZ for counterweight / ABC size for the motor
 
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Hello @cristofayre ,
:welcome: !​

cristofayre said:
Do the two sides cancel each other out?
Nope !

cristofayre said:
The metalwork is in ten "X" sections, each approx 1kg, and extends to 5mtrs. One kg weight on the end. The counterweight side has 1.5 "X" sections.
Can you draw that for us ? I can't visualize a 'counterweight side' ?

1614031575762.png
 
crane.jpg

The first diagram is how the 'accordian' fits together, with 1kg at the front of 5mtrs, and the "1.5", (actually 2 sections) behind the pivot with a c/w. The blue circle is the fulcrum/pivot. Second picture is how it could operate, between this and horizontal, as well as extendding from 1mtr to 5mtr. Third pic is where I envisaged putting the motor to 'drive' the middle pivots to extend / decrease frame size.

Hope that helps
 
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