- #1

Alexander1

- 13

- 0

## Homework Statement

Hi guys, I'm currently working on a homework question but I'm a little bit stuck although I do know what I'm meant to be doing. My question asks me to find the torque being caused by a beam pulling down on another. I'll explain a little more the context of it - there is one beam (beam 1) spanning across from point A to point B, and one end is attached at the top of point A and the other is attached at the top of point B . Right beside that beam (beam 1) which spans across from point A to point B is another beam (beam 2). This beam however only spans half the way out and one end is attached at the top of point A. Beam 2 is securely attached all the way along beam 1 and is therefore causing it to twist due to the downwards forces.

## Homework Equations

So far I know that I need to use the formula: Torque=Force x Radius x sinQ

I think that should be all that is involved although I might have to use rotational equilibrium

## The Attempt at a Solution

I have worked out the radius like this: (looking at a cross section of the end of the beams - beam 2 on left and beam 1 on right) I have assumed the pivot is in the centre of beam 1 and the radius is from there to the furthest edge of beam 2. Is this correct or do I need to work it out using rotational equilibrium or something?

sinQ: Would be sin90

Force: I think that I would need to find the reaction force being applied at each end of beam 2 (secured side will be acting up and the side secured to the edge of beam 1 will be acting down). By finding the reaction force that the beam is creating on point A I can then find the reaction force at the other end of beam 2 (I'm not sure how to do that? Or is it equal except negative?) This is what I'm not sure how to do though. I have the weight and length of all of the beams too.

Any help regarding finding the reaction forces and radius would be greatly appreciated.

Thanks, Alex