Functional groups present are: C=O and NH2

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The discussion centers on the protonation behavior of amines, specifically why nitrogen (N) is protonated more readily than carbonyl oxygen (C=O) despite oxygen's higher electronegativity and lone pair availability. Key points include that the lone pairs on oxygen can be delocalized, making them less available for protonation. Additionally, when nitrogen is protonated, the resulting cation can stabilize through hydrogen bonding with water, enhancing the stability of the nitrogen cation compared to an oxygen cation. It is noted that nitrogen holds its electrons less tightly than oxygen, making the positive charge on nitrogen more favorable due to its lower electronegativity. The discussion also raises questions about the mechanisms of lone pair delocalization on oxygen.
garytse86
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This is about amines:

The functional groups present are: C=O and NH2

Why does the N get protonated always but not C=O, since the oxygen has more lone pairs and more electronegative than N so shouldn't the oxygen be protonated more easily? I can't think of any good reasons... please help :confused:
 
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In some cases note that the lone pairs on the oxygen are delocalized, and thus less available in a sense. In some cases, protonation of the nitrogen atom to its corresponding cation will be reinforced by hydrogen bonding of water to the newly formed compound (4 hydrogens in contrast to 3). Also, nitrogen holds its electrons less tightly.
 
An alternate explanation: A positive charge on nitrogen is better than a positive charge on oxygen because nitrogen is less electronegative.
 
Thanks. But how can the lone pairs of oxygen be delocalised?
 
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