Functions [f(x)] and substituton

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To evaluate and simplify [f(x+h) - f(x)]/h for f(x) = x^2 - 2x, one must first correctly substitute f(x+h) with (x+h)^2 - 2(x+h). The initial approach of simply plugging in values led to confusion, as it overlooked the need to fully expand and simplify the expression. After substituting and simplifying, the correct form reveals that the expression reduces to h/h, which equals 1, but the process requires careful attention to detail. The discussion emphasizes the importance of understanding function substitution, as this concept will be crucial in future calculus studies. Mastering this technique is essential for success in calculus and related topics.
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Homework Statement


Evaluate and simpliy [f(x+h) - f(x)]/h if f(x) = x^2 -2x


Homework Equations


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The Attempt at a Solution


I just plugged in f(x), or x^2 - 2x for f(X+h) and f(x) and burned it down to h/h, or 1.
That sounds too easy, though...want to know if it's correct.
 
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You should show your work. If f(x)=x^2-2x, then what is f(x+h)?
 
if f(x) = 2x + 1
then f(x+h) = 2(x+h) + 1
 
cristo said:
You should show your work. If f(x)=x^2-2x, then what is f(x+h)?

Would it simply be x^2 - 2x + h?
(That may be where the problem is...I'm not too sure on that)

If so, I just did:

x^2 - 2x + h - x^2 + 2x --> h ---numerator
h --- denominator

h/h = 1?

EDIT - I see what you did...(rocophysics)
Thanks! I'll try it out.
 
Last edited:
No, it wouldn't. The variable in f(x) is x, whereas the variable in f(x+h) is (x+h): i.e. you need to write (x+h) in place of x in the original function.
 
If f(x) = x^2+2x then what would say f(3) be? f(3)=(3)^2+2(3) right? So what is f(x+h)?
 
If f(x) = x^2, then f(x+h) = (x+h)^2 = x^2 + 2xh + h^2
 
Feldoh said:
If f(x) = x^2+2x then what would say f(3) be? f(3)=(3)^2+2(3) right? So what is f(x+h)?

Right...so f(x+h) is:

(x+h)^2 - 2x + 2h
I foiled out everything, and I think I'm good to go :)
Thanks for the help!
 
Tekee said:
Right...so f(x+h) is:

(x+h)^2 - 2x + 2h
I foiled out everything, and I think I'm good to go :)
Thanks for the help!

f(x) = 2(x)
f(3) = 2(3)
f(x+h) = 2(?)

Other then that (x+h)^2 looks right. :)

All f(x+h) means is go to the function and every where you see an "x" replace it with "x+h"
 
  • #10
better learn this good! you'll encounter it around the ~2nd chapter of your Calculus book.
 
  • #11
rocophysics said:
better learn this good! you'll encounter it around the ~2nd chapter of your Calculus book.

^^He's got a point [f(x+h) - f(x)]/h will be revisited -- A LOT
 
  • #12
Tekee said:
Right...so f(x+h) is:

(x+h)^2 - 2x + 2h
I foiled out everything, and I think I'm good to go :)
Thanks for the help!

But you're original function was x^2-2x so replacing x with x+h you should have
(x+h)^2-2(x+h). Can you expand this? You are off by a sign somewhere in your post, do you see where?
 
  • #13
i remember our first test ... lots of ppl did bad b/c of this concept

they sure were happy when they learned how to take the derivative :)
 
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