Functions for which f(nx) is a polynomial of f(x).

AI Thread Summary
The discussion centers on identifying functions f(x) such that f(nx) can be expressed as a polynomial in f(x) with integer coefficients. Examples provided include trigonometric functions like cos(x), exponential functions such as e^(nx), and linear functions like ax + b. Participants explore the possibility of more complex polynomials, questioning whether there are functions with more than two terms that fit this criterion. The conversation also touches on the implications of polynomial degrees and the potential for generating sequences of higher-degree polynomials. Ultimately, the inquiry seeks to uncover non-trivial polynomial solutions of degree greater than two.
Boorglar
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What are some examples of functions such that

f(nx) = a_{k}f(x)^{k}+...+a_{1}f(x)+a_{0}

for some integers n, k, and integer coefficients in the polynomial?

The only example I can think of is cos(x), for which \cos(2x) = 2\cos(x)^{2}-1 and there are similar relations for n = 3, 4, etc.

Are these the only possible examples expressible in terms of elementary functions?
 
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e^{nx} = (e^x)^n

f(x) = ax + b

log(nx) = log(x) + log n
 
Ah yes I didn't think of those.

Are there any more "exotic" examples?
I mean, for which the polynomial involved has more than 2 terms, say?
 
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Nicely factored polynomials let you write the opposite of polynomials (instead of integer terms, 1/k terms)

f(x) = (x+1)^2
Then
f(nx) = (nx+1)^2 = n^2(x+1/n)^2 = n^2 (x+1+(1/n-1))^2
= n^2 ( (x+1)^2 + 2(x+1)(1/n-1) + (1/n-1)^2)
= n^2(f(x)+ (1/n-1) f(x)^{1/2} + (1/n-1)^2)

I can't figure out a way to jigger it (make it negative degree terms, fractional terms etc) to make it a true polynomial but maybe someone else can see how to do it
 
Interesting idea for the fractional powers. Unfortunately I don't think polynomials will work for the relationship.

Suppose
f(x) = a_{k}x^{k}+...+a_{0} and g(x) = b_{l}x^{l}+...+b_{0}

where f(nx) = g(f(x))

The LHS has degree k, while the RHS has degree k*l, which is greater than k unless l is 1, which corresponds to f(nx) = b_{1}f(x)+b_{0}.
 
Boorglar said:
Are there any more "exotic" examples?
I mean, for which the polynomial involved has more than 2 terms, say?

If f(nx) = P(f(x)) then f(n^2x) = f(n(nx)) = P(f(nx)) = P(P(f(x)). If the degree of the polynomial P(x) > 1 you can build a sequence of higher degree polynomials by changing n to powers of itself.

If we define the lowest possible n to be a "non-trivial" solution, the question can be rephrased to ask for examples where a non-trivial solution is a polynomial of degree greater than 2.

If we have a particular polynomial G(x) in mind then we can ask for the smallest n such that there is some polynomial P(x) of smaller degree than G(x) and G(x) is a member of the sequence of polynomials that are built-up in the above fashion. Thats a question for a good algebraist and I'm not sure how the answer bears on the original question - I'll use the excuse that it past 3AM in my time zone.
 
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