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i have this function(taken from fourier analysis):

n - 1,2,3...

f(x) = cos( (2*pi*n)/L * x )

the literature says this function has L period (n parameter):

f(x + L) = cos( (2*pi*n)/L * (x + L) ) =

= cos( 2*pi*n/L * x + 2*pi*n) = cos( 2*pi*n/L * x)

so it's true thatLf's period for any n.....

butL/nis also f's period because:

f(x + L/n) = cos( (2*pi*n)/L * (x + L/n) ) =

= cos( 2*pi*n/L * x + 2*pi) = cos( 2*pi*n/L * x)

so what happens here??

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# Function's period

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