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## Homework Statement

A stretched wire vibrates in its fundamental mode at a frequency of 400Hz. What would be the fundamental frequency if the wire were half as long, with twice the diameter and with four times the tension?

## Homework Equations

fn = nV / 2L where n is the harmonics number. f1 is the fundmental frequency.

i think i should be using

V= Sqrt(T/u)

## The Attempt at a Solution

how do i start? this is what i got...

since it gave 400Hz... then i think i should use...

fn = nV/2L -----> 400Hz = V/2L

therefore V= 400 * 2L

using V= Sqrt ( T/u) ---> 400*2L= Sqrt( T/U) ----

i am stuck here...i have a hunch that i need to find something it term of something that play back the two equation..afterwhich it will cancel out something..then i can get the value...dunno where to go from here...any hel thanks??