A stretched wire vibrates in its fundamental mode at a frequency of 400Hz. What would be the fundamental frequency if the wire were half as long, with twice the diameter and with four times the tension?
fn = nV / 2L where n is the harmonics number. f1 is the fundmental frequency.
i think i should be using
The Attempt at a Solution
how do i start? this is what i got...
since it gave 400Hz... then i think i should use...
fn = nV/2L -----> 400Hz = V/2L
therefore V= 400 * 2L
using V= Sqrt ( T/u) ---> 400*2L= Sqrt( T/U) ----
i am stuck here...i have a hunch that i need to find something it term of something that play back the two equation..afterwhich it will cancel out something..then i can get the value...dunno where to go from here...any hel thanks??