- #1
cjf
- 3
- 0
To improve my understanding of physics I was unable find the answer to this
question on the web after a lot of searching so I'll try here.
let v= net velocity of the x direction and the y direction
You take a particle at rest with mass m and you accelerate it to 80% of c in the x direction it appears to have the mass = m/(1-v^2/c^2}^1.5 when
resisting acceleration in the x direction.
Now you accelerate the particle moving at 80% of c in the x direction with an electric field which now accelerates the particle in the y direction with no force acting in x direction,
my question is does the particle appear to have the mass=m/(1-v^2/c^2)^1.5 or mass=m/(1-v^2/c^2)^.5 when resisting acceleration in the y direction.
question on the web after a lot of searching so I'll try here.
let v= net velocity of the x direction and the y direction
You take a particle at rest with mass m and you accelerate it to 80% of c in the x direction it appears to have the mass = m/(1-v^2/c^2}^1.5 when
resisting acceleration in the x direction.
Now you accelerate the particle moving at 80% of c in the x direction with an electric field which now accelerates the particle in the y direction with no force acting in x direction,
my question is does the particle appear to have the mass=m/(1-v^2/c^2)^1.5 or mass=m/(1-v^2/c^2)^.5 when resisting acceleration in the y direction.