Fundamental Theorem for Line Integrals

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SUMMARY

The discussion focuses on the application of the Fundamental Theorem for Line Integrals to the vector field F = <6x + 2y, 2x + 5y>. The user successfully derived the potential function f(x, y) = 3x² + 2xy + (5/2)y² and is seeking clarification on evaluating the line integral along the curve C defined by r(t) = for 0 < t < 1. The integral setup involves substituting the parameterization into the vector field and calculating the integral from 0 to 1, confirming that both the potential function and the contour integral yield the same result.

PREREQUISITES
  • Understanding of vector fields and line integrals
  • Familiarity with the Fundamental Theorem for Line Integrals
  • Knowledge of parameterization of curves in multivariable calculus
  • Ability to compute derivatives and integrals of functions
NEXT STEPS
  • Study the application of the Fundamental Theorem for Line Integrals in different vector fields
  • Learn how to parameterize curves in three-dimensional space
  • Explore advanced techniques for evaluating line integrals, such as Green's Theorem
  • Investigate the relationship between conservative vector fields and potential functions
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Students and professionals in mathematics, physics, and engineering who are working with vector calculus and line integrals, particularly those seeking to deepen their understanding of the Fundamental Theorem for Line Integrals.

andyk23
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Vector field F(bar)= <6x+2y,2x+5y>
fx(x,y)= 6x+2y fy(x,y)= 2x+5y
f(x,y)= 3x^2+2xy+g(y)
fy(x,y)=2x+g'(y)
2x+g'(y)= 2x+5y
g'(y)= 5y
g(y)= 5/2*y^2
f(x,y)=3x^2+2xy+(5/2)y^2
Then find the [itex]\int[/itex] F(bar)*dr(bar) along curve C t^2i+t^3j, 0<t<1
I'm stuck on finding the last part for the F(bar) would I use <6x+2y,2x+5y> and substitute the <t^2,t^3> in the for x&y then do F(bar)* rbar'(t)
so [itex]\int[/itex] from 0 to 1 of <6t^2+2t^3,2t^2+5t^3> <2t,3t^2>
Thanks for the help
 
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You figured out a potential for your vector field. You could use that to do the integral. And then you set up the explicit contour integral. Both look correct. They give you the same answer, don't they?
 

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