Fundemental lemma of the calculus of variations

TooFastTim
Messages
12
Reaction score
0

Homework Statement



Hi, I've been revising the calculus of variations and using the wiki entry on the euler lagrange equation (http://en.wikipedia.org/wiki/Euler-Lagrange_equation) as a reference. Scroll down and you'll see: Derivation of one-dimensional Euler–Lagrange equation. Expand this. In it you'll see the statement: "It follows from the total derivative that" and:

dF/dε= dx/dε*∂F/∂x + dgε/dε*∂F/∂gε + dg'ε/dε*∂Fε/∂g'ε

Homework Equations



What happened to the first term (dx/dε*∂F/∂x)?

The Attempt at a Solution



I understand that the first term has gone to zero. But how? If π(a) and π(b) both = 0 surely f(x) is a line with f(x) = 0? In which case it is clear that that term will go to zero.
 
Physics news on Phys.org
Isn't ##dx/d\varepsilon =0##?
 
I think I have it. The description in wiki is a little limited (alternatively my imagination is limited :smile:) so by a little mixing and matching of proofs I think I have found it.

Thanks anyway.
 
I don't see any obvious problem with the derivation on Wikipedia other than it throws in the unnecessary term that seems to have confused you.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top