Galilean transform and Lorentz transform questions

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The discussion clarifies the application of the Galilean and Lorentz transforms in relation to moving and stationary observers. It confirms that the Galilean transform can determine Alice's position from Bob's perspective and vice versa, but does not apply when considering Bob as the moving observer with Alice stationary. Similarly, the Lorentz transform operates under the same principles, allowing for the conversion of coordinates between different rest frames. The conversation emphasizes that both transforms facilitate understanding the relationship between observers in motion. Additionally, there is a request for resources to practice problems related to Galilean transforms.
rgtr
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Homework Statement
I am just curious about the Galilean transform and the Lorentz Transform
Relevant Equations
## x = x'+vt ##
## x = gamma(x'+vt') ##
I have a quick question about the Galilean transform. If I have Alice running and Bob stationary. The Galilean transform will tell me the position of Alice from Bob's stationary position. Also if I have Alice's position which is moving it will tell me Bob's stationary position.

If I want Bob moving and Alice stationary that is not what the Galilean transform does. Is this correct?

I have not gotten to it yet but previously have read a little bit about the Lorentz transform for position the same logic applies as above.

If I want Bob moving and Alice stationary that is not what the Lorentz transform does. Is this correct?
 
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rgtr said:
The Galilean transform will tell me the position of Alice from Bob's stationary position. Also if I have Alice's position which is moving it will tell me Bob's stationary position.
No, it will not. It will tell you how the coordinates of an event in Alice and Bob’s rest frames relate to each other.
rgtr said:
Homework Statement:: I am just curious about the Galilean transform and the Lorentz Transform
Relevant Equations:: ## x = x'+vt ##
## x = gamma(x'+vt') ##

If I want Bob moving and Alice stationary that is not what the Lorentz transform does. Is this correct?
No. Both going back and forth between their rest frames are Galilean/Lorentz transformations (which depending on whether you do classical mechanics or special relativity).
 
Thanks for that clarification. Any idea where I could practice a few questions about Galilean transforms?
 
Thread 'Chain falling out of a horizontal tube onto a table'
My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...

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