Galous Group Modules Self Study: Q&A

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I was doing some self study and have questions:
1. p(x)=x^{7}+11 over Q(a), R.
where a is 7-th root of unity. What are Galouis groups?
For the 1st case I got Z_{7}, second not sure. need hint for that
2. need hint. I know it is easy: M is an R-module. Show that Hom_{R}(R,M)\congM.
3. Spse that I is an ideal of R such that I^{k}=0 for some k>0 integer. Let M, N be R-modules and let \phi:M->N be an R-module hom. Prove that if induced map \bar{\phi}:M/IM->N/IN is surjective, then \phi is surjective.
4. show that 2\otimes1 \neq0 in 2Z\otimesZ/2Z.
 
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2. You need a map from

{f : R-->M } to M

(or vice versa).Assuming that R is unital, then there is only one possible map you can write down:

f ---> f(1)

You have to try to show that is an isomorphism. You also may want to think about the other direction;

M --> {f: R --> M}

again, there is only one possible map you can write down - given m in M, then the only candidate in Hom_R(R,M) is translation by m:

f_m(r)= r.m

so you have to show that the map m--->f_m is an isomorphism (note we've dropped the explicit use use R being unital).
 
matt grime said:
2. You need a map from

{f : R-->M } to M

(or vice versa).


Assuming that R is unital, then there is only one possible map you can write down:

f ---> f(1)
This is what I tried. g(f)=f_{1}. But I had hard time showing that it is surjective
 
Have you tried working to find an inverse? The second part of my hint wasn't just decoration.
 
matt grime said:
Have you tried working to find an inverse? The second part of my hint wasn't just decoration.

yeah, i got it. thanks
 
#3 is somewhat tricky. The key is to prove that \varphi(IM) = IN. This can be done by induction on k, but first you'll need a lemma to the effect that if \bar{\varphi} is surjective, then the induced map \psi_r : I^r M/I^{r+1} \to I^r N/I^{r+1} is surjective for all r.

Let me think about the others some more...I'll get back to you in a bit. (Although #4 looks pretty trivial.)
 
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