Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

A Gauge transformations at infinity

  1. Apr 16, 2017 #1
    Consider the following paragraph taken from page 15 of Thomas Hartman's lecture notes (http://www.hartmanhep.net/topics2015/) on Quantum Gravity:

    In an ordinary quantum field theory without gravity, in flat spacetime, there two types of physical observables that we most often talk about are correlation functions of gauge-invariant operators ##\langle O_{1}(x_{1}) \dots O_{n}(x_{n})\rangle##, and S-matrix elements. The correlators are obviously gauge-independent. S-matrix elements are also physical, even though electrons are not gauge invariant. The reason is that the states used to define the S-matrix have particles at infinity, and gauge transformations acting at infinity are true symmetries. They take one physical state to a different physical state - unlike
    local gauge transformations, which map a physical state to a different description of the same physical state.


    ------------------------------------------------------------------------------------------------------------------------------------------------------

    1. What does it mean for electrons to not be gauge invariant and how could this have possibly mucked up the gauge-independence of the S-matrix elements?

    2. Why are gauge transformations acting at infinity true symmetries which take take one physical state to a different physical state?
     
  2. jcsd
  3. Apr 16, 2017 #2

    vanhees71

    User Avatar
    Science Advisor
    2016 Award

Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Gauge transformations at infinity
  1. Gauge transformations (Replies: 3)

Loading...