- #1

KillerZ

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## Homework Statement

A spherically symmetric charge distribution produces the electric field [tex]E = (5000r^2) N/C[/tex], where r is in m.

a) What is the electric field strength at r = 20cm?

b) What is the electric flux through a 40cm diameter spherical surface that is concentric with the charge distribution?

c) How much charge is inside this 40cm diameter spherical surface?

## Homework Equations

[tex]E = (5000r^2) N/C[/tex]

## The Attempt at a Solution

I am not sure if I did this right?

a)

[tex]E = (5000r^2) N/C[/tex]

[tex]E = (5000(0.2m)^2) N/C[/tex]

= [tex]200 Nm^2/C[/tex]

b)

40cm = diameter

20cm = radius

[tex]E = (5000(0.2m)^2) N/C[/tex]

= [tex]200 Nm^2/C[/tex]

c)

[tex]\phi_{e}=\frac{q}{\epsilon_0}[/tex]

[tex]q=(\phi_{e})(\epsilon_0)[/tex]

[tex]q=(200 Nm^2/C)(8.85x10^{-12} C^2/Nm^2)[/tex]

[tex]= 1x10^{-9} C[/tex]