Gauss's Law:Metal sphere of radius 'a' surrounded by a shell

Click For Summary

Homework Help Overview

The problem involves a metal sphere of radius 'a' surrounded by a thick concentric metal shell with inner radius 'b' and outer radius 'c'. A point charge +Q is located inside an irregular cavity within the sphere. The discussion revolves around the induced charges on the surfaces and the electric fields in different regions.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to analyze the induced charges and electric fields in various regions, noting the relationships between the charges and the surfaces. Some participants question the wording of part b), specifically whether it refers to the charge density at the outer surface of the sphere or the shell.

Discussion Status

Participants have provided feedback on the original poster's attempts, with some expressing agreement on the correctness of the reasoning. However, there is an ongoing discussion about the clarity of the problem statement, particularly regarding the terminology used in part b).

Contextual Notes

There is a mention that the homework problem is based on a similar problem from Griffith's text, which may influence the language used by the instructor. The potential inconsistency in the problem statement regarding the term "sphere" and its implications for the charge density is under consideration.

jinksys
Messages
122
Reaction score
0

Homework Statement



A metal sphere of radius a is surrounded by a thick concentric metal shell (inner radius b, outer radius c). Neither the shell nor the sphere carries any charge, but there is a point charge +Q located inside an irregularly shaped cavity in the otherwise solid sphere as shown in the figure. The irregular cavity is not concentric with the sphere.

a) Sketch the induced charges on all the relevant surfaces.
b) What is the surface density of the charge on the outer surface of the sphere r=c?
c) What is the electric field where a<r<b?
c) What is the electric field where b<r<c?


The Attempt at a Solution



a) The positive charge within the irregular cavity will induce a negative charge on the surface of the cavity. This will in turn induce a positive charge on the surface of the sphere. A negative charge will be induced on the surface at b and a positive charge will be induced on the surface at c. This is illustrated in this image.

b) Q=σA where A=area of surface.
σ=Q/A
σ=Q/(4πc^2)

c) E=1/(4πε0) * Q/r^2
The total enclosed charge is Q.

d) This point is inside the metal shell so the E-field should be zero.
The enclosed charges are +Q from the sphere and -Q from the 'b' surface. The net charge is zero, so E= 1/(4πε0) * 0/r^2 == 0.

I'm using Griffith's E+M text.
 
Physics news on Phys.org
'Looks correct to me. :approve:

[Just out of curiosity though, part b) uses the word "sphere" but then has "r=c" which would imply outer radius of the "shell." Maybe it's nothing, sometimes shells are called spheres. But it seems a little inconsistent for Griffiths. Are you sure that part b) isn't asking you for charge density at r = a?]
 
Last edited:
collinsmark said:
'Looks correct to me. :approve:

:smile: Awesome, thanks!
 
jinksys said:
:smile: Awesome, thanks!
In case you missed my edit (which I didn't update until after your last post), I'll repeat it again here:

Just out of curiosity though, part b) uses the word "sphere" but then has "r=c" which would imply outer radius of the "shell." Maybe it's nothing, sometimes shells are called spheres. But it seems a little inconsistent for Griffiths. Are you sure that part b) isn't asking you for charge density at r = a?
 
collinsmark said:
In case you missed my edit (which I didn't update until after your last post), I'll repeat it again here:

Just out of curiosity though, part b) uses the word "sphere" but then has "r=c" which would imply outer radius of the "shell." Maybe it's nothing, sometimes shells are called spheres. But it seems a little inconsistent for Griffiths. Are you sure that part b) isn't asking you for charge density at r = a?

My homework problem is based off a similar problem in griffith's, so its the teacher's language and not Griffith's. Part-b says (verbatim) What is the surface density of charge on the outer surface of the sphere (r=c)?
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 49 ·
2
Replies
49
Views
7K
Replies
23
Views
5K
Replies
5
Views
1K
Replies
4
Views
5K
  • · Replies 10 ·
Replies
10
Views
5K
Replies
4
Views
5K
  • · Replies 6 ·
Replies
6
Views
6K
  • · Replies 6 ·
Replies
6
Views
2K