General Formula For Reflection Direction

AI Thread Summary
A particle's reflection direction upon colliding with a wall varies based on the wall's orientation, with different formulas for horizontal and vertical tangents. For horizontal surfaces, the reflection direction is calculated as 180 minus the incidence angle, while for vertical surfaces, it is 360 minus the incidence angle. A general formula that applies to both scenarios has been proposed: C = 2B - A, where A is the incidence angle and B is the angle normal to the wall. This formula effectively accounts for the 90-degree difference between normal and tangent angles. The discussion concludes with gratitude for clarifying the general formula needed.
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An Example Scenario:

A particle moves at 32° and collides with a wall. This wall is rectangular in nature, which means that there is both horizontal and vertical sides.

On a horizontal tangent, it would work like this (sorry for ugly, not-to-scale diagrams):

[PLAIN]http://img198.imageshack.us/img198/7808/questionsc.jpg
(reflects at 148°)

However, on a vertical tangent it would reflect like this:

[PLAIN]http://img808.imageshack.us/img808/2064/question2.png
(reflects at 328°)

This means that:
  • On horizontal tangent: reflectionDirection = 180-incidenceDirection
  • On vertical tangent: reflectionDirection = 360-incidenceDirection

It's lame to have two different formulas, so is there a general formula for the reflectionDirection that works with both vertical and horizontal tangents? It's fine if it uses radians instead of degrees.
 
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If the incoming angle is A, and B is an angle normal to the wall, then the reflected angle C is given by C = B - A.
 
Thanks, but that was not what I was looking for.

In case someone else needs to know, the general formula is:

C = 180+2B-A

Where A is the direction of incidence, B is the direction of tangent (0 if horizontal, 90 if vertical) and C is the direction of reflection.
 
Well the normal and tangent angles are 90 degrees different, so it all works.

Also, I meant C = 2B - A in my last post, sorry.
 
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