General Physics Problem (Velocitys)

AI Thread Summary
In a race between a hare and a tortoise over 1.00 km, the tortoise moves steadily at 0.200 m/s, taking 5,000 seconds to finish. The hare runs at 8.00 m/s, reaching 800 m in 1,000 seconds before stopping to taunt the tortoise. To determine how close the hare can let the tortoise approach before resuming the race, calculations show that the hare can start again 200 m from the finish line. The tortoise, moving at its constant speed, covers a distance during the hare's pause that needs to be accounted for to ensure a photo finish. The key is to analyze the time the hare spends taunting and the distance the tortoise covers in that time.
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. Homework Statement
A hare and a tortoise compete in a race over a course of 1.00km long. The tortoise crawls straight and steadily at its max speed of 0.200 m/s toward the finish line. the hare runs at its max speed of 8.00 m/s toward the goal for .800km and then stops to taunt the tortoise. how close to the goal can the hare let the tortoise approach before resuming the race, which the tortoise win in a photo finish? assume that, when moving, both animals move steadily at there respective max speeds.

3. The Attempt at a Solution
I kinda feel stupid. I know it takes 5,000 seconds for the tortoise to go 1000m, 4,000 to go 800m, and 1,000 to go the last 200m.
It takes 1,250 seconds for the hare to go the whole 1000m, 1,000 seconds to go too the 800m mark, and 250 seconds to go the last 200m of the race.

Just not sure how to put this together.
 
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It easier if you split it up and work from both ends at the same time. The hare went .8km and then stopped. Where is the tortoise then? If the race ended at a photo finish and the hare started again 200m from the finish line, how far did the tortoise run after the hare started again? The difference between those two tortoise positions is how far the tortoise ran while the hare was taunting. How long was it taunting?
 
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