Generating Chlorine from Ca(OCl)2 and HCl: 50.0g & 275 mL

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Chlorine gas can be generated by reacting calcium hypochlorite (Ca(OCl)2) with hydrochloric acid (HCl), producing calcium chloride and water as byproducts. The reaction is identified as a redox process, but the focus is on determining the limiting reagent. For the given quantities of 50.0g of Ca(OCl)2 and 275mL of 6.00M HCl, participants are calculating the moles of each reactant to identify which is in excess. Initial calculations suggest 0.35 moles of Ca(OCl)2 and 1.4 moles of HCl, but there is a request for verification of these values. Accurate calculations are essential for determining the mass of chlorine gas produced and identifying the excess reactant.
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Chlorine can be generated by heating together calcium hyperchlorite and hydrochloric acid. Calcium chloride and water are also formed.

a) If 50.0g of Ca(OCl)2 and 275mL of 6.00M HCL are allowed to react, how many grams of chlorine gas will form?

b) Which reactant will be in excess and what is its mass?


The attempt at a solution

Ca(ClO)2 + 4 HCl → CaCl2 + 2 H2O + 2 Cl2 is this a redox equation ? i don't know how to proceed. Any help would be would be appreciated ...
 
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Yes, this is redox - buit it doesn't matter. It is a (relatively) simple limiting reagent problem.

You have a correct reaction equation, calculate how many moles of both reactants you have. Which one is in excess?
 
i guess Ca(OCl)2 0.35 moles and 1.4 moles hcl is this right ?
 
Nothing to guess here, just calculate. One of your numbers is wrong.
 
Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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