Generating Circular Polarization

AI Thread Summary
The discussion centers on generating circular polarization using two dipole antennas oriented 90 degrees apart, with one radiating cos(ωt) and the other sin(ωt). The resulting electric field is expressed as a function of both time and distance from the antennas, where z represents the propagation direction. The participants clarify that β is related to the wavelength and not a phase shift, and they explain that a circularly polarized wave can change handedness upon reflection. The conversation also addresses the nature of the electric field's dependence on z and t, emphasizing that it is indeed a function of both variables. Overall, the thread provides insights into the mechanics of circular polarization and the behavior of electromagnetic waves.
jeff1evesque
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Statement:
Consider two dipole antennas, oriented 90degrees apart [imagine the x-y plane, let "a" be the dipole oriented along the x-axis, and the "b" be the dipole oriented along the y-axis]. If "a" dipole radiates cos(\omega t) and "b" dipole radiates sin(\omega t), the field radiated by the two antennas will be circularly polarized:

\vec{E}(z, t) = E_{0}[cos(\omega t - \beta z)\hat{x} + sin(\omega t - \beta z)\hat{y}] (#1)

Side note: Very often, helical antennas are used to generate a circularly-polarized (CP) wave. The isolation between a left-handed CP wave and a right-handed CP wave can be significant. Also, a CP wave will change handedness upon reflection.

My thoughts:
I understand that E_0 is the magnitude of the sinusoid- and in this case it is circular thus both \hat{x}, \hat{y} have the same amplitudes respectively. And since both sin(\omega t), cos(\omega t) are perpendicular to one another, if one has a phase shift, the other will have the same phase shift \beta.

Relevant questions:
Is my thoughts above reasonable? What I would really like to know is why the electric field is a function of z also. What is the variable z, and how does it influence the electric field?

Also, can someone explain to me what is meant by
Also, a CP wave will change handedness upon reflection?
Thanks,Jeffrey
 
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jeff1evesque said:
My thoughts:
I understand that E_0 is the magnitude of the sinusoid- and in this case it is circular thus both \hat{x}, \hat{y} have the same amplitudes respectively. And since both sin(\omega t), cos(\omega t) are perpendicular to one another, if one has a phase shift, the other will have the same phase shift \beta.

Relevant questions:
Is my thoughts above reasonable? What I would really like to know is why the electric field is a function of z also. What is the variable z, and how does it influence the electric field?
Your thoughts look pretty reasonable, but β is not a phase shift. z is the distance away from the antenna in the direction of the E-M wave's propagation, and β=2π/λ is related to the wavelength λ.

Those equations represent a wave traveling in the +z direction. At any fixed time t, the electric field direction makes a rotating, helical pattern as one moves along the z direction.

I'm not familiar with helical antennas, so I can't comment on them.

Also, can someone explain to me what is meant by

Also, a CP wave will change handedness upon reflection.
The wave changes from right-handed to left-handed (or vice versa) CP if it is reflected.
 
Redbelly98 said:
Your thoughts look pretty reasonable, but β is not a phase shift. z is the distance away from the antenna in the direction of the E-M wave's propagation, and β=2π/λ is related to the wavelength λ.

Shouldn't z be \hat{z} then? So if it becomes the unit vector (since that is the direction of propagation), then the electric field cannot be a function of z, and thus should it be a function of \beta instead- along with t?

Thanks,Jeff
 
No, it is z. The electric field is a function of z and t.
 
Redbelly98 said:
No, it is z. The electric field is a function of z and t.

Ok I almost get it now. I am going to start a new thread, this one is getting long.THanks,JL
 
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