Generating the Borel-algebra from half-open intervals

  • Thread starter Thread starter dane502
  • Start date Start date
  • Tags Tags
    intervals
dane502
Messages
20
Reaction score
0
Hi everybody!

I have been asked to show that the Borel-algebra can be generated from the set of half-open intervals of the form [a , b) where a<b.

I know that the set of open intervals of the form (a,b) where a<b generates the Borel-algebra and thought I would go about showing that the to sets generates the same δ-algebra. But that has proven more difficult than I thought.

Can anybody give me an direction?


Any help is greatly appreciated!
dane502
 
Physics news on Phys.org
Can you write the open intervals as a union of halfopen intervals?

dane502 said:
Hi everybody!

I have been asked to show that the Borel-algebra can be generated from the set of half-open intervals of the form [a , b) where a<b.

I know that the set of open intervals of the form (a,b) where a<b generates the Borel-algebra and thought I would go about showing that the to sets generates the same δ-algebra. But that has proven more difficult than I thought.

Can anybody give me an direction?


Any help is greatly appreciated!
dane502
 
micromass said:
Can you write the open intervals as a union of halfopen intervals?

Thank you for your answer.

No, the half-open intervals has to be on the form of [a,b), so any union of those half-open intervals (that is not disjoint) will also have form [a,b).
 
dane502 said:
Thank you for your answer.

No, the half-open intervals has to be on the form of [a,b), so any union of those half-open intervals (that is not disjoint) will also have form [a,b).

Sure of that?
 
Think of

\bigcup [a-1/n,b)
 
micromass said:
Think of

\bigcup [a-1/n,b)

Thank you. Somehow I missed that.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top