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I was reading Tom Apostol's expostion of Euler's Summation Formula ( http://www.jstor.org/pss/2589145) and it occurred to me that it would be convenient to visualize
\int_a^b x f'(x)
geometrically.
In that article, it arises from integration by parts:
\int_a^b f(x) dx = |_a^b x f(x) - \int_a^b x f'(x) dx
Visualize an increasing function f(x) in the first quadrant. The area given by |_a^b x f(x) = b f(b) - a f(a) is the area of a big rectangle minus the are of a smaller rectangle. This are includes the area given by \int_a^b f(x) dx.
The area from the subtraction of the rectangular areas exceeds the area of that integral by an area that I can visualize as begin formed by horizontal line segments from the x-axis to the the curve of f(x) between the lines y= f(a) and y = f(b). In the integration by parts, the term \int_a^b x f'(x) dx apparently subtracts that excess area in order to produce the right answer.
So, would it be good pedagogy to teach this as the geometric interpretation of \int_a^b x f'(x) dx ? Is it in any textbook? I think it works out in the case when f(x) is decreasing also, since the sign of f'(x) makes the area negative.
\int_a^b x f'(x)
geometrically.
In that article, it arises from integration by parts:
\int_a^b f(x) dx = |_a^b x f(x) - \int_a^b x f'(x) dx
Visualize an increasing function f(x) in the first quadrant. The area given by |_a^b x f(x) = b f(b) - a f(a) is the area of a big rectangle minus the are of a smaller rectangle. This are includes the area given by \int_a^b f(x) dx.
The area from the subtraction of the rectangular areas exceeds the area of that integral by an area that I can visualize as begin formed by horizontal line segments from the x-axis to the the curve of f(x) between the lines y= f(a) and y = f(b). In the integration by parts, the term \int_a^b x f'(x) dx apparently subtracts that excess area in order to produce the right answer.
So, would it be good pedagogy to teach this as the geometric interpretation of \int_a^b x f'(x) dx ? Is it in any textbook? I think it works out in the case when f(x) is decreasing also, since the sign of f'(x) makes the area negative.
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