Okay, so I know(adsbygoogle = window.adsbygoogle || []).push({});

[tex]C=Q/ΔV[/tex]

And ΔV is the sum of the electric fields multiplied by the distance between the charges, so if the first charge has a charge of Q and the other has -Q with R distance between, the electric potential/voltage is:

[tex]ΔV = [(kQ/r^2) + (kQ/r^2)]R[/tex]

so

[tex]ΔV = 2kQ/R[/tex].

And [tex]C = Q/ΔV[/tex]

so...

[tex]C = Q/(kQ/R)[/tex]

and...

[tex]C = R/2k[/tex]

and...

[tex]C = R/2[1/(4Πε_0)][/tex]

and

[tex]C = 2ΠRε_0[/tex]

What...?

It would make some semblance of sense if R were inversely proportional to capacitance, but it isnt...

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# Getting weird formula for Capacitance

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