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The electric potential can be defined as

V = - ∫

where we are taking the line integral along C from some convenient reference point

Doesn't this mean d

I am aware that we can fix this by taking

EDIT: This seems like it'd fit better in General Physics. Woops.

V = - ∫

_{C}**E**⋅d**l**where we are taking the line integral along C from some convenient reference point

**O**, where we have set V = 0, to the point**r**we are trying to find the potential at. Of course, C can be any curve, but it's usually the most convenient to take it as a straight line from**O**to**r**.Doesn't this mean d

**l**will point in the direction from**O**to**r**? If that is the case, then say we're trying to find the potential at some distance from point charge +q and we've set our reference point infinitely far away. We have**E**= (kq/r^2)**r**(hat), where**r**(hat) is the spherical unit vector. Then,**E⋅**d**l**= E**r**(hat)⋅d**l**. But d**l**points from infinity to the point we're trying to find, and say that we've picked**O**so that d**l**points in the -**r**(hat) direction. Then,**E⋅**d**l**= -Edr, so evaluating the integral, we get V = -kq/r, which is evidently wrong.I am aware that we can fix this by taking

**O**to be somewhere else, but do you always take the line integral to be positive? If so, why? Or is there something else I'm missing?EDIT: This seems like it'd fit better in General Physics. Woops.

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