Give an example of such a convergent series

gas8
Messages
2
Reaction score
0

Homework Statement



Give an example of a convergent series \Sigma z_{n}

So that for each n in N we have:

limsup abs{\frac{z_{n+1}}{z_{n}}} is greater than 1
 
Physics news on Phys.org


How about combining the convergent series 2^(-n) and 3^(-n) in a clever way? Hint: alternate terms from each.
 


yeah thx, I used 2^(-n) when n is even and 2^-(n+1 ) when n is odd
 


gas8 said:
yeah thx, I used 2^(-n) when n is even and 2^-(n+1 ) when n is odd

Something like that will work, but doesn't that just give you limsup=1?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top