Given a DNA sequence, which will be its mRNA?

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The discussion focuses on the conversion of a DNA sequence (3’-TAC-CGA-TAT-AGC-CGT-ATT-5’) into its corresponding mRNA sequence (5’-AUG-GCU-AUA-UCG-GCA-UAA-3’) and the resulting peptide sequence, which includes a start codon, alanine, isoleucine, serine, alanine, and a stop codon. The significance of the 3' and 5' notation is clarified, indicating that these refer to the carbon positions of the pentose sugar in the nucleotide structure. Flipping the 3' and 5' positions would reverse the sequence order, affecting the translation process.

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stonecoldgen
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And what will be the peptide sequence formed?

So the sequence is: ADN 3’- TAC-CGA-TAT-AGC-CGT-ATT -5’

so my guess is that it's AUG-GCU-AUA-UCG-GCA-UAA and the peptide sequence is: Start codon, alanin, isoleucine, serine, alanin, stop codon.

My question is: What do those 3's and 5's mean? How would the answer change if their positions were flipped?
 
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3' and 5' refers to the carbon of the pentode sugar to which that particular Nitro base is attached to,
If it's flipped the sequence would be in reverse order.
 

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