Given ∆Hf = -607 kJ/mol and S = 417 J, find ∆H and ∆S

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The discussion revolves around calculating ∆H and ∆S for the reaction involving Ni and CO to form Ni(CO)4, given the standard enthalpy of formation (∆Hf) and entropy (S) values. The user expresses confusion due to a mismatch in their lab and lecture schedules, resulting in a lack of understanding of thermodynamics concepts. They found potential answers online but need to show their work for homework. Other participants suggest consulting textbooks and provide links to relevant resources, emphasizing the importance of understanding the underlying equations rather than just seeking answers. The conversation highlights the challenge of balancing coursework with practical application and the need for foundational knowledge in thermodynamics.
AMan24
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Homework Statement


Ni (s) + 4 CO(g) ↔ Ni(CO)4(g)

For Ni(CO)4(g), ∆Hf = -607 kJ/mol and S = 417 J/mol⋅K at 298 K. Using these values and data in the Appendix of your text, calculate ∆H and ∆S for the above reaction.

Homework Equations


no idea

The Attempt at a Solution


I don't know how to solve this, because my lab class somehow ended up a week ahead of lecture, so i haven't even learned thermodynamics yet.

I think i found the answers online but i need to show work.
∆S°= -409.5 J/K
∆H° =−160.8 kJ

I'm trying to look up formulas right now and find something i can use.
 
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AMan24 said:
I don't know how to solve this, because my lab class somehow ended up a week ahead of lecture, so i haven't even learned thermodynamics yet.
Don't you have a textbook?

We can't do your work for you, but have a look at http://chem.libretexts.org/Core/Phy...tions/Enthalpy/Standard_Enthalpy_Of_Formation
https://www.chem.tamu.edu/class/majors/tutorialnotefiles/enthalpy.htm
https://www.chem.tamu.edu/class/majors/tutorialnotefiles/gibbs.htm
 
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Hae can you define it clearly ∆H° is for and also∆s°
 
Can you send the questions image
 
Timakki said:
Can you send the questions image

heres the image if it helps

boBmFEm.png
 
DrClaude said:
Don't you have a textbook?
We can't do your work for you, but have a look at

Yeah i don't want to come across like I'm hoping someone will do the work for me, i really try to avoid posting things like this.

I do have a textbook, but i didn't want to read the entire chapter in one night so i could answer one question. I was hoping someone could just tell me the equations and i could plug them in.

I'll take a look at the links you posted tomorrow.
 
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