Given velocity and acceleration, determine magnetic field

AI Thread Summary
The discussion focuses on determining the magnetic field components given an electron's velocity and acceleration in an electric field. The velocity is 1.20 x 10^4 m/s in the positive x direction, and the acceleration is 2.00 x 10^12 m/s^2 in the positive z direction, with an electric field of 20.0 N/C in the positive z direction. The magnetic field components are found to be Bx (any value), By = -2.6 mT, and Bz = 0. The discussion also touches on the ethics of homework help, questioning whether credit is given to those who assist with such questions. The conversation emphasizes the importance of understanding the physics behind the calculations.
yanyin
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an electron has a velocity of 1.20 x 10^4 m/s(in the positive x direction), and an acceleration of 2.00 x 10^12 m/s^2 (in the positive z direction) in a uniform electric and magnetic field. if the electric field has magnitude of 20.0N/C (in the positive z direction), what can you determine about the magnetic field in the region? what can you not determine?
(Please show steps and why, the correct answers i got are Bx(any value), By = -2.6mT, Bz=0)
 
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Originally posted by yanyin
an electron has a velocity of 1.20 x 10^4 m/s(in the positive x direction), and an acceleration of 2.00 x 10^12 m/s^2 (in the positive z direction) in a uniform electric and magnetic field. if the electric field has magnitude of 20.0N/C (in the positive z direction), what can you determine about the magnetic field in the region? what can you not determine?
(Please show steps and why, the correct answers i got are Bx(any value), By = -2.6mT, Bz=0)

Do we get the credit instead of you if we answer your homework/take-home exam question?
 
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