Golf Club Air Friction: Mass, Velocity & Acceleration Effects

  • Thread starter Thread starter drinkingstraw
  • Start date Start date
  • Tags Tags
    Air Friction
drinkingstraw
Messages
23
Reaction score
0
Im talking about the friction between a golf club and the air as the golf club is swinging towards the ball. how does the mass of the club, the velocity of the swing and the acceleration affect the friction acting on the club and how much will it slow down?

I know the formuls is Ffrict = coefficent of friction (norrmal force)

so if the force applied is greater then the force of friction will be less?
 
Physics news on Phys.org
drinkingstraw said:
Im talking about the friction between a golf club and the air as the golf club is swinging towards the ball. how does the mass of the club, the velocity of the swing and the acceleration affect the friction acting on the club and how much will it slow down?

I know the formuls is Ffrict = coefficent of friction (norrmal force)

so if the force applied is greater then the force of friction will be less?

Hi drinkingstraw! :smile:

That isn't friction … it's viscosity.

Friction is where the material doesn't move, viscosity is where it gets dragged along, and/or has to get out of the way.

Whole different subject. :wink:
 
tiny-tim said:
Hi drinkingstraw! :smile:

That isn't friction … it's viscosity.

Friction is where the material doesn't move, viscosity is where it gets dragged along, and/or has to get out of the way.

Whole different subject. :wink:

Well that certainly changes things. Thanks :)
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
Back
Top