Grade 11 Physics: A subway train

Click For Summary
SUMMARY

The discussion focuses on calculating the total distance traveled by a subway train and its average speed during a journey involving three phases: acceleration, constant speed, and deceleration. The train accelerates at 2.0 m/s² for 10 seconds, travels at a constant speed for 30 seconds, and then decelerates at 2.4 m/s² until it stops. By applying kinematic equations, participants can determine the distance covered in each phase and subsequently calculate the average speed of the train.

PREREQUISITES
  • Kinematic equations for uniformly accelerated motion
  • Understanding of acceleration and deceleration concepts
  • Basic algebra for solving equations
  • Knowledge of average speed calculation
NEXT STEPS
  • Study the kinematic equations in detail, focusing on distance and speed calculations
  • Explore examples of constant acceleration scenarios in physics
  • Learn about real-world applications of acceleration and deceleration in transportation
  • Investigate the impact of varying acceleration rates on travel time and distance
USEFUL FOR

Students studying physics, particularly those in Grade 11, educators teaching motion concepts, and anyone interested in understanding the dynamics of train travel and acceleration principles.

soniaFB
Messages
1
Reaction score
0
A subway train starts from rest at a station and accelerates at the rate of 2.0m/s^2 for 10s. It runs at a constant speed for 30s, and then decelerates at 2.4m/s^2 until it stops at the next station.

Find the total distance between the stations and the average speed of the train.
 
Physics news on Phys.org
Well first I'd see that you need to break this down into 3 separate problems.
1) Train accelerating at the rate of 2.0m/s^2 for 10s
2) Going at constant speed for 30s
3) Decelerating at 2.4m/s^2 until it stops

Notice that the problems involving an acceleration have constant accelerations, so you can you all of the kinematic equations to solve for the distance. After that, the last part should be fairly simple
 

Similar threads

Replies
20
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
7K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
1
Views
7K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
8
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K