Gradient of a potential energy function

[Radarithm]

Homework Statement

Find the derivative of \frac{Q}{4\pi \epsilon_0 r}

Homework Equations

\frac{d}{dx} \frac{1}{x}=\ln x

The Attempt at a Solution

Assuming Q and the rest of the variables under it are constant, \frac{Q}{4\pi \epsilon_0}\frac{1}{r} then the derivative should be \ln r. I am taking the gradient of a potential energy function but since it is in one dimension (r in this case isn't a 2-3 dimensional vector) it is the same as taking the derivative. Is my answer correct or did I make a mistake somewhere?

 

[Mentallic]

You have it the wrong way around.

\frac{d}{dx}\ln{x}=\frac{1}{x}

 

[Radarithm]

You have it the wrong way around.

\frac{d}{dx}\ln{x}=\frac{1}{x}

Yep, thanks for correcting me. The derivative is then \frac{-1}{r^2} from the power rule, correct?

 

[Mentallic]

Correct.