Graph Analysis: Determining Absolute Extreme Values on a Closed Interval [a,b]

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SUMMARY

The discussion centers on determining absolute extreme values of a function on a closed interval [a, b] based on its continuity. Theorem 1 asserts that a function f(x) must be continuous on [a, b] to guarantee the existence of maximum and minimum values. A participant argues that the graph in question is not continuous, leading to the conclusion that no extreme values exist. However, another participant clarifies that the book states the converse is false, emphasizing that the existence of extreme values does not imply continuity.

PREREQUISITES
  • Understanding of Theorem 1 regarding continuity and extreme values
  • Familiarity with the concepts of maximum and minimum values in calculus
  • Knowledge of graph analysis techniques
  • Basic understanding of logical statements and converses
NEXT STEPS
  • Study the implications of Theorem 1 in calculus
  • Learn about continuity and discontinuity in functions
  • Explore graph analysis for identifying extreme values
  • Review logical reasoning in mathematical statements and their converses
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Students of calculus, mathematics educators, and anyone interested in understanding the relationship between continuity and extreme values in functions.

donjt81
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Please see attached image for reference.

Here is the problem. Determine from the graph whether the function has any absolute extreme values on [a, b]. Then explain how your answer is consistent with Theorem 1.

So Theorem 1 is the one that states f(x) has a maximum and minimum if F(x) is continuous on a closed interval [a,b]

If you look at the image you will see the graph. I think that this graph is not continuous. And so I said there is no maximum or minimum. but the book says maximum x = c minimum x = a. So I guess this graph is continuous according to the book. but how is the attached image continuous in the interval [a,b]
 

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So I guess this graph is continuous according to the book.
The book never said that...
 
The book says that
"If a function, f(x) is continuous on the closed, bounded, interval [a,b] then f(x) takes on maximum and minimum values in the interval".

It does NOT say
"If a function takes on maximum and minimum values on [a, b] then it is continuous on the interval". That is the "converse" of the book statement and is FALSE!

(If a statement says "if A then B", its converse is "If B then A". A statement being true does NOT mean its converse is.)
 

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